Question

a 5.23 g sample of a metal occupies 0.27 ml. identify the density of the metal. view available hint(s) 19 g/ml 5.2×10^{-2} g/ml 19.3 g/ml 19.37037037 g/ml

Explanation:

Step1: Recall the density formula

Density formula is \(d=\frac{m}{V}\), where \(m\) is mass and \(V\) is volume.

Step2: Substitute the given values

Given \(m = 5.23\space g\) and \(V=0.27\space mL\). Then \(d=\frac{5.23}{0.27}\).

Step3: Calculate the value

\(\frac{5.23}{0.27}\approx19.37\). But considering significant - figures, \(5.23\) has three significant figures and \(0.27\) has two. When dividing, the result should have two significant figures. \(19.37\approx19\) (rounded to two significant figures).

Answer:

19 g/mL