Question

q.22. the table shows the melting points and boiling points for different substances. identify the state of given substances at room temperature (room temperature is around 20°c).

Explanation:

Step1: Analyze Water

For water, melting point is \(0^{\circ}C\) and boiling point is \(100^{\circ}C\). Room temperature \(20^{\circ}C\) is between \(0^{\circ}C\) and \(100^{\circ}C\). So water is in liquid state.

Step2: Analyze Oxygen

Oxygen has melting point \(- 218^{\circ}C\) and boiling point \(-183^{\circ}C\). Room temperature \(20^{\circ}C> - 183^{\circ}C\). So oxygen is in gas state.

Step3: Analyze Iron

Iron has melting point \(1538^{\circ}C\). Room temperature \(20^{\circ}C<1538^{\circ}C\). So iron is in solid state.

Step4: Analyze Sulfuric acid

Sulfuric acid has melting point \(10.3^{\circ}C\) and boiling point \(337^{\circ}C\). Room temperature \(20^{\circ}C\) is between \(10.3^{\circ}C\) and \(337^{\circ}C\). So sulfuric acid is in liquid state.

Step5: Analyze Magnesium

Magnesium has melting point \(650^{\circ}C\). Room temperature \(20^{\circ}C<650^{\circ}C\). So magnesium is in solid state.

Step6: Analyze Nitrogen

Nitrogen has melting point \(-210^{\circ}C\) and boiling point \(-195^{\circ}C\). Room temperature \(20^{\circ}C> - 195^{\circ}C\). So nitrogen is in gas state.

Answer:

	State at Room Temperature
Oxygen	gas
Iron	solid
Sulfuric acid	liquid
Magnesium	solid
Nitrogen	gas