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what is the value of t? $t-23^\\circ$ $t-12^\\circ$ $t+48^\\circ$ $t = …

$t=83^\circ$

分類: geometry 更新時間: 2026-02-09

題目

what is the value of t?
$t-23^\\circ$
$t-12^\\circ$
$t+48^\\circ$
$t = \\square^\\circ$
submit
work it out
not feeling ready yet? these can help:
solve linear equations: mixed review
angle measures

解題步驟

  1. Understand the question

    what is the value of t?
    $t-23^\\circ$
    $t-12^\\circ$
    $t+48^\\circ$
    $t = \\square^\\circ$
    submit
    work it out
    not feeling ready yet? these can help:
    solve linear equations: mixed review
    angle measures

  2. Explanation

    Step1: Use exterior angle property

    The exterior angle of a triangle equals the sum of the two non-adjacent interior angles. So:
    $$t+48^\circ=(t-23^\circ)+(t-12^\circ)$$

    Step2: Simplify right-hand side

    Combine like terms on the right:
    $$t+48^\circ=2t-35^\circ$$

    Step3: Isolate variable $t$

    Subtract $t$ and add $35^\circ$ to both sides:
    $$48^\circ+35^\circ=2t-t$$
    $$83^\circ=t$$

  3. Final answer

    $t=83^\circ$

答案

Explanation

Step1: Use exterior angle property

The exterior angle of a triangle equals the sum of the two non-adjacent interior angles. So:
$$t+48^\circ=(t-23^\circ)+(t-12^\circ)$$

Step2: Simplify right-hand side

Combine like terms on the right:
$$t+48^\circ=2t-35^\circ$$

Step3: Isolate variable $t$

Subtract $t$ and add $35^\circ$ to both sides:
$$48^\circ+35^\circ=2t-t$$
$$83^\circ=t$$

Answer

$t=83^\circ$

Question Image

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Question Analysis

Subject mathematics
Sub Subject geometry
Education Level high school
Difficulty unspecified
Question Type with image, calculation
Multi Question No
Question Count 1
Analysis Status completed
Analyzed At 2026-02-09T20:26:21

OCR Text

Show OCR extraction
what is the value of t?
$t-23^\\circ$
$t-12^\\circ$
$t+48^\\circ$
$t = \\square^\\circ$
submit
work it out
not feeling ready yet? these can help:
solve linear equations: mixed review
angle measures

相關知識點

mathematicsgeometrywith image, calculationhigh schoolturns-1

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