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20) $ac^2 + a$; use $a = -1$, and $c = 3$

Question

  1. $ac^2 + a$; use $a = -1$, and $c = 3$

Explanation:

Step1: Substitute the values of \(a\) and \(c\) into the expression.

Given \(a = -1\) and \(c = 3\), substitute into \(ac^{2}+a\):
\((-1)\times(3)^{2}+(-1)\)

Step2: Calculate the exponent.

First, calculate \(3^{2}\):
\(3^{2}=9\)
So the expression becomes \((-1)\times9+(-1)\)

Step3: Perform the multiplication.

Calculate \((-1)\times9\):
\((-1)\times9=-9\)
Now the expression is \(-9+(-1)\)

Step4: Perform the addition.

Add \(-9\) and \(-1\):
\(-9+(-1)=-10\)

Answer:

\(-10\)