Question

1st semester exam
solve for the indicated variable: $3h = 2x + 4y$, solve for $y$
$\bigcirc\\ \frac{4h - 2x}{4}$
$\bigcirc\\ \frac{3h - 2x}{4}$
$\bigcirc\\ \frac{h - x}{4}$
$\bigcirc\\ \frac{h - 2x}{2}$

Explanation:

Step1: Isolate the term with y

Subtract \(2x\) from both sides of the equation \(3h = 2x + 4y\) to get \(3h - 2x = 4y\).

Step2: Solve for y

Divide both sides of the equation \(3h - 2x = 4y\) by 4. So \(y=\frac{3h - 2x}{4}\).

Answer:

\(\boldsymbol{\frac{3h - 2x}{4}}\) (corresponding to the option \(\frac{3h - 2x}{4}\))