Question

1. the length of another rectangle was 6.2 inches. the width of the rectangle was 3.1 inches. find the perimeter of this rectangle.

Explanation:

Step1: Recall the formula for the perimeter of a rectangle

The formula for the perimeter \(P\) of a rectangle is \(P = 2\times(\text{length}+\text{width})\). Let \(l = 6.2\) inches (length) and \(w=3.1\) inches (width).

Step2: Substitute the values into the formula

Substitute \(l = 6.2\) and \(w = 3.1\) into \(P = 2\times(l + w)\). So \(P=2\times(6.2 + 3.1)\).
First, calculate the sum inside the parentheses: \(6.2+3.1=9.3\).
Then, multiply by 2: \(P = 2\times9.3\).

Step3: Perform the multiplication

\(2\times9.3=18.6\).

Answer:

\(18.6\) inches