Question

1. calculate the stress at failure of a concrete test cylinder with a measured diameter of 152.4 mm and a recorded load of 371 426 n.

Explanation:

Step1: Calculate the cross - sectional area

The formula for the area of a circle is \(A=\pi r^{2}\), where \(r\) is the radius. Given \(d = 152.4\space mm\), then \(r=\frac{d}{2}=\frac{152.4}{2}=76.2\space mm\).

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Convert \(mm^{2}\) to \(m^{2}\): \(1\space m = 1000\space mm\), so \(1\space m^{2}=(1000)^{2}\space mm^{2}\). Then \(A = 18237.1\times10^{- 6}\space m^{2}\)

Step2: Calculate the stress

The formula for stress \(\sigma=\frac{F}{A}\), where \(F\) is the force and \(A\) is the cross - sectional area. Given \(F = 371426\space N\)

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Answer:

The stress at failure is \(20.37\space MPa\)