Question

1. if $overrightarrow{np}$ bisects $angle mnq$, $mangle mnq=(8x + 12)^{circ}$, $mangle pnq = 78^{circ}$, and $mangle rnm=(3y - 9)^{circ}$, find the values of $x$ and $y$.

Explanation:

Step1: Use angle - bisector property

Since $\overrightarrow{NP}$ bisects $\angle MNQ$, then $m\angle MNQ = 2m\angle PNQ$. Given $m\angle MNQ=(8x + 12)^{\circ}$ and $m\angle PNQ = 78^{\circ}$, we have the equation $8x+12 = 2\times78$.
$8x+12=156$

Step2: Solve for $x$

Subtract 12 from both sides of the equation: $8x=156 - 12$.
$8x=144$
Divide both sides by 8: $x=\frac{144}{8}=18$.

Step3: Use vertical - angle property

$\angle PNQ$ and $\angle RNM$ are vertical angles. Vertical angles are equal, so $m\angle RNM=m\angle PNQ$. Given $m\angle RNM=(3y - 9)^{\circ}$ and $m\angle PNQ = 78^{\circ}$, we set up the equation $3y-9 = 78$.

Step4: Solve for $y$

Add 9 to both sides of the equation: $3y=78 + 9$.
$3y=87$
Divide both sides by 3: $y=\frac{87}{3}=29$.

Answer:

$x = 18$, $y = 29$