Question

1. an apple was cut into 8 equal - size pieces. stacy ate $\frac{1}{4}$ of the apple. tony ate $\frac{3}{8}$ of the apple. what part of the apple did stacy and tony eat in all?

\textcircled{a} $\frac{1}{2}$
\textcircled{b} $\frac{5}{8}$
\textcircled{c} $\frac{3}{4}$
\textcircled{d} $\frac{1}{4}$

Explanation:

Step1: Make the denominators the same

To add \(\frac{1}{4}\) and \(\frac{3}{8}\), we need a common denominator. The least - common denominator of \(4\) and \(8\) is \(8\). We rewrite \(\frac{1}{4}\) as \(\frac{1\times2}{4\times2}=\frac{2}{8}\).

Step2: Add the fractions

Now we add \(\frac{2}{8}\) and \(\frac{3}{8}\). Using the rule \(\frac{a}{c}+\frac{b}{c}=\frac{a + b}{c}\) (where \(c = 8\), \(a=2\), \(b = 3\)), we get \(\frac{2+3}{8}=\frac{5}{8}\).

Answer:

B. \(\frac{5}{8}\)