Question

e. 16
23.according to the following diagram, which three options represent light emission?
(select all options that apply)

n = 4
n = 3
(a)
(e)
n = 2
(b)
(d)
(f)
n = 1

a. a
b. b
c. c
d. d
e. e
f. f

Explanation:

In atomic physics (a subfield of Physics, which is under Natural Science), light emission occurs when an electron transitions from a higher energy level (higher \( n \)) to a lower energy level (lower \( n \)). This is represented by downward - pointing arrows in the energy - level diagram.

• Option (a): The arrow goes from \( n = 4 \) to \( n = 2 \) (downward), so it represents light emission.
• Option (b): The arrow goes from \( n = 1 \) to \( n = 4 \) (upward), which is absorption, not emission.
• Option (c): The arrow goes from \( n = 4 \) to \( n = 3 \) (downward), so it represents light emission.
• Option (d): The arrow goes from \( n = 1 \) to \( n = 2 \) (upward), which is absorption, not emission.
• Option (e): The arrow goes from \( n = 2 \) to \( n = 4 \) (upward), which is absorption, not emission.
• Option (f): The arrow goes from \( n = 1 \) to \( n = 4 \) (upward), which is absorption, not emission. Wait, no, let's re - check. Wait, the correct downward transitions (emission) are (a) (from \( n = 4 \) to \( n = 2 \)), (b)? No, (b) is upward? Wait, no, in the diagram, (a) is from \( n = 4 \) to \( n = 2 \) (down), (b) is from \( n = 1 \) to \( n = 4 \) (up)? Wait, no, the labels: (a) is from \( n = 4 \) to \( n = 2 \) (down), (b) is from \( n = 1 \) to \( n = 4 \) (up)? Wait, no, looking at the diagram again: (a) is \( n = 4 \) to \( n = 2 \) (down), (b) is \( n = 1 \) to \( n = 4 \) (up)? No, (b) is a downward arrow from \( n = 4 \) to \( n = 1 \)? Wait, maybe I misread the direction. Let's re - examine the diagram:

The energy levels are \( n = 1 \) (lowest), \( n = 2 \), \( n = 3 \), \( n = 4 \) (highest). So:

• (a): \( n = 4

ightarrow n = 2 \) (down) - emission.

• (b): \( n = 4

ightarrow n = 1 \) (down) - emission.

• (c): \( n = 4

ightarrow n = 3 \) (down) - emission.

• (d): \( n = 1

ightarrow n = 2 \) (up) - absorption.

• (e): \( n = 2

ightarrow n = 4 \) (up) - absorption.

• (f): \( n = 1

ightarrow n = 4 \) (up) - absorption.

Wait, maybe my initial mis - reading of (b). So the correct downward (emission) arrows are (a), (b), (c).

Answer:

a. a, b. b, c. c