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15. divide: $left(-3\frac{1}{3} ight) div left(+1\frac{1}{9} ight)$

Question

  1. divide: $left(-3\frac{1}{3}

ight) div left(+1\frac{1}{9}
ight)$

Explanation:

Step1: Convert mixed numbers to improper fractions

$ -3\frac{1}{3} = -\frac{3\times3 +1}{3}=-\frac{10}{3} $, $ +1\frac{1}{9} = \frac{1\times9 +1}{9}=\frac{10}{9} $

Step2: Rewrite division as multiplication by reciprocal

$ -\frac{10}{3} \div \frac{10}{9} = -\frac{10}{3} \times \frac{9}{10} $

Step3: Simplify and calculate

$ -\frac{10\times9}{3\times10} = -\frac{9}{3} = -3 $

Answer:

$-3$