Question

1. x ? 3 in z 14 in y xz =

Explanation:

Step1: Apply Pythagorean theorem

$$XZ^{2}=XY^{2}+YZ^{2}$$

Step2: Substitute values

Given \(XY = 3\) in and \(YZ=14\) in. Then \(XZ^{2}=3^{2}+14^{2}=9 + 196=205\)

Step3: Solve for \(XZ\)

\(XZ=\sqrt{205}\approx14.32\) in

Answer:

\(XZ\approx14.32\) in