Question

1. a person spat out their gum on the roof of a building and fell for 3 seconds. how far did it fall?

Explanation:

Step1: Identify the free - fall formula

The formula for the distance fallen in free - fall is $d = v_0t+\frac{1}{2}gt^2$, where $v_0$ is the initial velocity, $t$ is the time, and $g$ is the acceleration due to gravity. Since the gum starts from rest, $v_0 = 0$. The acceleration due to gravity near the Earth's surface is approximately $g = 9.8\ m/s^2$.

Step2: Substitute the values into the formula

With $v_0 = 0$, the formula simplifies to $d=\frac{1}{2}gt^2$. Substitute $g = 9.8\ m/s^2$ and $t = 3\ s$ into the formula: $d=\frac{1}{2}\times9.8\times3^2$.

Step3: Calculate the distance

First, calculate $3^2=9$. Then, $\frac{1}{2}\times9.8\times9 = 4.9\times9=44.1\ m$.

Answer:

$44.1\ m$