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Question
13 multiple choice 2 points the diameter below represents a planet revolving in an elliptical orbit around a star. as the planet makes one complete revolution around the star, starting at the position shown, the gravitational attraction between the star and the planet will decrease, then increase increase, then decrease continually decrease remain the same 14 multiple choice 2 points one complete cycle of the phases of the moon takes approximately one day week month year
Step1: Recall Newton's law of universal gravitation
The gravitational force \(F = G\frac{m_1m_2}{r^2}\), where \(G\) is the gravitational constant, \(m_1\) and \(m_2\) are the masses of the two objects (star and planet), and \(r\) is the distance between them.
Step2: Analyze the distance change in an elliptical orbit
In an elliptical orbit, when the planet moves from the initial position: first, it moves away from the star (distance \(r\) increases, so \(F\) decreases as \(F\propto\frac{1}{r^{2}}\)), then it moves closer to the star (distance \(r\) decreases, so \(F\) increases as \(F\propto\frac{1}{r^{2}}\)).
The lunar phase cycle is related to the Moon's orbit around the Earth. The time it takes for the Moon to complete one full cycle of phases (from new - moon to new - moon) is approximately 29.5 days, which is close to a month.
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decrease, then increase