Question

13 here is an example of a balanced chemical equation = 2h₂ + 1o₂ → 2h₂o balance the following chemical equation: □ b + □ f₂ → □ bf₃

Explanation:

Step1: Balance fluorine atoms

Let the coefficients of \(B\), \(F_2\), and \(BF_3\) be \(a\), \(b\), and \(c\) respectively. The chemical equation is \(aB + bF_2
ightarrow cBF_3\).
For fluorine atoms: \(2b = 3c\). Let's first balance \(F\). The least - common multiple of \(2\) and \(3\) (the sub - scripts of \(F\) in \(F_2\) and \(BF_3\)) is \(6\). So if \(2b=6\), then \(b = 3\); if \(3c=6\), then \(c = 2\).

Step2: Balance boron atoms

For boron atoms: \(a=c\). Since \(c = 2\), then \(a=2\).

The balanced chemical equation is \(2B+3F_2
ightarrow 2BF_3\)

Answer:

\(2\), \(3\), \(2\)