Question

12x²+13x−35

1. −ab(2ab−a+4b)

Explanation:

Step1: Distribute -ab to each term inside the parentheses

Using the distributive property \( c(a + b + d) = ca + cb + cd \), we have:
\( -ab \times 2ab + (-ab) \times (-a) + (-ab) \times 4b \)

Step2: Multiply the terms

For the first term: \( -ab \times 2ab = -2a^{1 + 1}b^{1 + 1} = -2a^{2}b^{2} \) (using the rule \( x^m \times x^n = x^{m + n} \))
For the second term: \( (-ab) \times (-a) = a^{1 + 1}b = a^{2}b \)
For the third term: \( (-ab) \times 4b = -4ab^{1 + 1} = -4ab^{2} \)

Step3: Combine the results

Putting it all together, we get: \( -2a^{2}b^{2} + a^{2}b - 4ab^{2} \)

Answer:

\( -2a^{2}b^{2} + a^{2}b - 4ab^{2} \)