Question

122
course
ap precalculus
due tue, oct 21, 2025
perfect square trinomials

1. $9z^{2}-24z + 16$

Explanation:

Step1: Recall the formula for perfect - square trinomial

The formula for a perfect - square trinomial is \(a^{2}-2ab + b^{2}=(a - b)^{2}\).
For the given trinomial \(9z^{2}-24z + 16\), we can rewrite it as \((3z)^{2}-2\times3z\times4+4^{2}\). Here, \(a = 3z\) and \(b = 4\).

Step2: Apply the formula

According to the formula \(a^{2}-2ab + b^{2}=(a - b)^{2}\), substituting \(a = 3z\) and \(b = 4\), we get \((3z-4)^{2}\).

Answer:

\((3z - 4)^{2}\)