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Question
- margin of error: 0.04; confidence level: 99%; from a prior study, $hat{p}$ is estimated by 0.12. a) 254 b) 526 c) 18 d) 438
solve the problem. round the point estimate to the nearest thousandth.
- 32 randomly picked people were asked if they rented or owned their own home, 8 said they rented. obtain a point estimate of the proportion of homeowners. a) 0.750 b) 0.781 c) 0.250 d) 0.200
- 50 people are selected randomly from a certain population and it is found that 12 people in the sample are over 6 feet tall. what is the point estimate of the proportion of people in the population who are over 6 feet tall? a) 0.76 b) 0.24 c) 0.18 d) 0.50
use the given degree of confidence and sample data to construct a confidence interval for the population proportion
- n = 85, x = 49; 98% confidence a) 0.451 < p < 0.701 b) 0.471 < p < 0.681 c) 0.470 < p < 0.682 d) 0.450 < p < 0.702
- n = 130, x = 69; 90% confidence a) 0.461 < p < 0.601 b) 0.463 < p < 0.599 c) 0.459 < p < 0.603 d) 0.458 < p < 0.604
- of 346 items tested, 12 are found to be defective. construct the 98% confidence interval for the proportion of all such items that are defective. a) 0.0110 < p < 0.0584 b) 0.0154 < p < 0.0540 c) 0.0118 < p < 0.0576 d) 0.0345 < p < 0.0349
- when 328 college students are randomly selected and surveyed, it is found that 122 own a car. find a 99% confidence interval for the true proportion of all college students who own a car. a) 0.320 < p < 0.424 b) 0.310 < p < 0.434 c) 0.303 < p < 0.441 d) 0.328 < p < 0.416
- of 380 randomly selected medical students, 21 said that they planned to work in a rural community. find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community. a) 0.0280 < p < 0.0826 b) 0.0251 < p < 0.0854 c) 0.0360 < p < 0.0745 d) 0.0323 < p < 0.0782
- a study involves 607 randomly selected deaths, with 35 of them caused by accidents. construct a 98% confidence interval for the true percentage of all deaths that are caused by accidents. a) 3.56% < p < 7.97% b) 3.91% < p < 7.62% c) 3.33% < p < 8.21% d) 4.20% < p < 7.33%
- of 260 employees selected randomly from one company, 18.46% of them commute by carpooling. construct a 90% confidence interval for the true percentage of all employees of the company who carpool. a) 14.5% < p < 22.4% b) 12.3% < p < 24.7% c) 12.9% < p < 24.1% d) 13.7% < p < 23.2%
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(12) A. 254
(13) A. 0.750
(14) B. 0.24
(15) C. \(0.470 < p < 0.682\)
(16) A. \(0.461 < p < 0.601\)
(17) C. \(0.0118 < p < 0.0576\)
(18) C. \(0.303 < p < 0.441\)
(19) A. \(0.0280 < p < 0.0826\)
(20) B. \(3.91\% < p < 7.62\%\)
(21) A. \(14.5\% < p < 22.4\%\)