QUESTION IMAGE
Question
- chemical name: bromine trifluoride formula: brf3 lewis electron - dot structure: perspective drawing with bond angles: standard electron geometry: molecular geometry: hybridization of central atom: is the molecule polar, nonpolar, or ion?
Step1: Determine valence - electrons
Bromine (Br) has 7 valence electrons and each fluorine (F) has 7 valence electrons. For $BrF_3$, the total number of valence electrons is $7 + 3\times7=28$.
Step2: Draw Lewis structure
Place Br in the center and connect it to 3 F atoms with single bonds. Then distribute the remaining electrons to satisfy the octet rule. Br has 2 lone - pairs in addition to the 3 bonding pairs.
Step3: Find electron - geometry
Using the VSEPR (Valence - Shell Electron - Pair Repulsion) theory, with 5 electron groups (3 bonding pairs and 2 lone - pairs) around the central Br atom, the electron geometry is trigonal bipyramidal.
Step4: Determine molecular geometry
Ignoring the lone - pairs, the molecular geometry of $BrF_3$ is T - shaped.
Step5: Identify hybridization
The central Br atom has 5 electron groups, so the hybridization is $sp^3d$.
Step6: Determine polarity
The molecule is polar because the bond dipoles do not cancel out due to the T - shaped molecular geometry.
Lewis electron - dot structure: Br is in the center with 3 single bonds to F atoms and 2 lone - pairs on Br.
Perspective drawing with bond angles: The F - Br - F bond angles are approximately 86.2° due to the repulsion of lone - pairs.
Standard electron geometry: Trigonal bipyramidal
Molecular geometry: T - shaped
Hybridization of central atom: $sp^3d$
Is the molecule polar, non - polar, or ion? Polar
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Lewis electron - dot structure: Br is in the center with 3 single bonds to F atoms and 2 lone - pairs on Br.
Perspective drawing with bond angles: The F - Br - F bond angles are approximately 86.2°.
Standard electron geometry: Trigonal bipyramidal
Molecular geometry: T - shaped
Hybridization of central atom: $sp^3d$
Is the molecule polar, non - polar, or ion? Polar