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11. which of the following will have a smaller radius than its neutral …

Question

  1. which of the following will have a smaller radius than its neutral atom when it forms an ion?

○ cl
○ k
○ he
○ f

  1. why does the ionization energy (the energy needed to remove an electron) decrease as you move down a column of the periodic table?

○ the distance between the nucleus and the outer electrons increases.
○ the number of valence electrons increases.
○ the distance between the nucleus and the outer electrons decreases.
○ the number of protons decreases, decreasing the nuclear charge.

Explanation:

Question 11
Brief Explanations

To determine which atom has a smaller ionic radius than its neutral atom, we analyze the ion formation:

  • Cl: Gains an electron to form \( \text{Cl}^- \). Adding an electron increases electron - electron repulsion, so the ionic radius is larger than the neutral atomic radius.
  • K: Loses an electron to form \( \text{K}^+ \). Removing an electron (from the outermost shell) reduces the shielding effect, and the remaining electrons are pulled closer to the nucleus. So the ionic radius of \( \text{K}^+ \) is smaller than the atomic radius of K.
  • He: Is a noble gas with a stable electron configuration (\( 1s^2 \)) and does not readily form ions.
  • F: Gains an electron to form \( \text{F}^- \). The addition of an electron increases repulsion, making the ionic radius larger than the atomic radius.
Brief Explanations

Ionization energy is the energy required to remove an electron. When moving down a column (group) in the periodic table:

  • The number of electron shells increases. This means the distance between the nucleus and the outermost (valence) electrons increases.
  • As the distance increases, the attractive force between the nucleus and the valence electrons decreases. So, less energy is needed to remove an electron, and ionization energy decreases.
  • Analyzing the options:
  • "The number of valence electrons increases" is incorrect. In a group, the number of valence electrons is the same.
  • "The distance between the nucleus and the outer electrons decreases" is incorrect as the distance increases down a group.
  • "The number of protons decreases, decreasing the nuclear charge" is incorrect. The number of protons (nuclear charge) generally increases down a group, but the effect of increased distance is more dominant.
  • "The distance between the nucleus and the outer electrons increases" is correct.

Answer:

B. K

Question 12