Question

1. what is the final velocity if the initial velocity is 10 m/s and the change in velocity is 15 m/s?
2. if a force of 50 n is applied for 2 seconds, what is the impulse?
3. what is the change in velocity if the total force is 90 n and the mass is 10 kg and the total time is 3 seconds?
4. if the initial velocity is 20 m/s and the final velocity is 50 m/s, what is the change in velocity? show your work:

Explanation:

Question 11:

Step1: Recall velocity change formula

The formula for final velocity \( v_f \) is \( v_f = v_i + \Delta v \), where \( v_i \) is initial velocity and \( \Delta v \) is change in velocity.

Step2: Substitute values

Given \( v_i = 10 \, \text{m/s} \) and \( \Delta v = 15 \, \text{m/s} \), so \( v_f = 10 + 15 \).

Step1: Recall impulse formula

Impulse \( J \) is given by \( J = F \times t \), where \( F \) is force and \( t \) is time.

Step2: Substitute values

Given \( F = 50 \, \text{N} \) and \( t = 2 \, \text{s} \), so \( J = 50 \times 2 \).

Step1: Recall impulse-momentum theorem

Impulse \( J = F \times t \) and momentum change \( \Delta p = m \times \Delta v \), and \( J = \Delta p \), so \( F \times t = m \times \Delta v \). Rearranging for \( \Delta v \), we get \( \Delta v = \frac{F \times t}{m} \).

Step2: Substitute values

Given \( F = 90 \, \text{N} \), \( t = 3 \, \text{s} \), \( m = 10 \, \text{kg} \), so \( \Delta v = \frac{90 \times 3}{10} \).

Answer:

\( 25 \, \text{m/s} \)

Question 12: