Question

11 use the formula $f = g\frac{m_1m_2}{d^2}$, where

• f = the force of gravity
• g = universal gravitational constant
• $m_1$ and $m_2$ = masses of the two objects
• d = the distance between the centers of the two objects

what would result in the greatest gravitational force between two objects?

a halving the mass of object 1

b doubling the mass of object 1

c halving the distance between the two objects

d doubling the distance between the two objects

Explanation:

Step1: Analyze option A

If we halve the mass of object 1 (\(m_1\)), using the formula \(F = G\frac{m_1m_2}{d^2}\), the new force \(F_1=G\frac{\frac{1}{2}m_1m_2}{d^2}=\frac{1}{2}F\).

Step2: Analyze option B

If we double the mass of object 1 (\(m_1\)), the new force \(F_2 = G\frac{2m_1m_2}{d^2}=2F\).

Step3: Analyze option C

If we halve the distance (\(d\)), the new force \(F_3=G\frac{m_1m_2}{(\frac{d}{2})^2}=G\frac{m_1m_2}{\frac{d^2}{4}} = 4F\).

Step4: Analyze option D

If we double the distance (\(d\)), the new force \(F_4=G\frac{m_1m_2}{(2d)^2}=G\frac{m_1m_2}{4d^2}=\frac{1}{4}F\).

Answer:

C. halving the distance between the two objects