Question

1. solve the following equation.

-2(x + 3)+12x = 10x - 3(x + 1)
x=

Explanation:

Step1: Expand both sides

Expand $-2(x + 3)$ to $-2x-6$ and $-3(x + 1)$ to $-3x-3$. The equation becomes $-2x-6 + 12x=10x-3x - 3$.

Step2: Combine like - terms on both sides

On the left - hand side, $-2x+12x = 10x$, so the left - hand side is $10x-6$. On the right - hand side, $10x-3x=7x$, so the right - hand side is $7x - 3$. The equation is now $10x-6=7x - 3$.

Step3: Move the $x$ terms to one side and constants to the other

Subtract $7x$ from both sides: $10x-7x-6=7x-7x - 3$, which simplifies to $3x-6=-3$. Then add 6 to both sides: $3x-6 + 6=-3 + 6$, resulting in $3x=3$.

Step4: Solve for $x$

Divide both sides by 3: $\frac{3x}{3}=\frac{3}{3}$, so $x = 1$.

Answer:

$x = 1$