Question

1. a function is given: $f(x) = -5x + 7$. what is the value of $f(-3)$?

a. $f(-3) = 52$

b. $f(-3) = -8$

c. $f(-3) = 22$

d. $f(-3) = 8$

1. if $h(t) = -16t^2 + 60t + 3$, find $h(2)$.

a. $h(2) = 59$

b. $h(2) = 187$

c. $h(2) = -1$

d. $h(2) = 91$

Explanation:

Question 11

Step1: Substitute \( x = -3 \) into \( f(x) \)

Given \( f(x) = -5x + 7 \), replace \( x \) with \( -3 \): \( f(-3) = -5(-3) + 7 \)

Step2: Calculate the expression

First, \( -5(-3) = 15 \), then \( 15 + 7 = 22 \)? Wait, no, wait: Wait, \( -5\times(-3)=15 \), then \( 15 + 7 = 22 \)? Wait, no, let's recalculate: \( -5\times(-3) = 15 \), then \( 15 + 7 = 22 \)? Wait, but let's check again. Wait, \( f(x) = -5x + 7 \), so \( f(-3) = -5\times(-3) + 7 = 15 + 7 = 22 \)? Wait, but option c is \( f(-3)=22 \). Wait, but let's check the options again. Wait, maybe I made a mistake. Wait, \( -5\times(-3) = 15 \), 15 +7=22. So option c.

Wait, no, wait: Wait, \( -5x +7 \), when x=-3, it's -5*(-3) +7 = 15 +7=22. So the correct answer is c.

Step1: Substitute \( t = 2 \) into \( h(t) \)

Given \( h(t) = -16t^2 + 60t + 3 \), replace \( t \) with \( 2 \): \( h(2) = -16(2)^2 + 60(2) + 3 \)

Step2: Calculate each term

First, \( (2)^2 = 4 \), so \( -16\times4 = -64 \). Then, \( 60\times2 = 120 \). Now, substitute back: \( h(2) = -64 + 120 + 3 \)

Step3: Sum the terms

\( -64 + 120 = 56 \), then \( 56 + 3 = 59 \)? Wait, no: \( -64 + 120 = 56 \), 56 +3=59. So \( h(2)=59 \), which is option a.

Answer:

c. \( f(-3) = 22 \)

Question 12