Question

10 multiple choice 1 pointcu₂o copper oxide (i) copper (ii) oxide copper (i) oxide copper oxide

Explanation:

In naming ionic compounds with transition metals (like copper which can have multiple oxidation states), we use Roman numerals to indicate the oxidation state of the metal. In \(Cu_2O\), oxygen has an oxidation state of \(- 2\). Using the formula for ionic compounds (sum of oxidation states = 0), for \(Cu_2O\): let the oxidation state of \(Cu\) be \(x\). Then \(2x+(-2)=0\), so \(2x = 2\) and \(x = + 1\). The naming convention is \(\text{Metal (Roman numeral for oxidation state)} \text{Non - metal base name + ide}\). So \(Cu_2O\) is copper (I) oxide.

Answer:

Copper (I) Oxide