Question

1. ( x_{l2} ) in this circuit is

169.6 ω
94.2 ω
75.4 ω
41.9 ω

Explanation:

Step1: Recall the formula for inductive reactance

The formula for inductive reactance is \(X_{L}=2\pi fL\), where \(f\) is the frequency and \(L\) is the inductance.

Step2: Substitute the given values

Given \(f = 600\space Hz\) and \(L_2=25\times10^{-3}\space H\) (since \(25\space mH=25\times 10^{-3}\space H\)), substitute into the formula:
\(X_{L2}=2\pi\times600\times25\times 10^{-3}\)
First, calculate \(2\times600\times25\times10^{-3}=30\), then multiply by \(\pi\approx3.14\)
\(X_{L2}=30\times3.14 = 94.2\space\Omega\)

Answer:

B. \(94.2\space\Omega\)