Question

a 10 - kg mass is thrown with an initial velocity of 9 m/s from an initial height of 12 meters. what is the magnitude of the initial kinetic energy component of the system? (1 point)
1,176 joules
405 joules
1,581 joules
771 joules

Explanation:

Step1: Recall the formula for kinetic energy

The formula for kinetic energy is \(K = \frac{1}{2}mv^{2}\), where \(m\) is the mass and \(v\) is the velocity.

Step2: Substitute the given values into the formula

Given \(m = 10\space kg\) and \(v=9\space m/s\). Then \(K=\frac{1}{2}\times10\times9^{2}\).
First, calculate \(9^{2}=81\). Then \(\frac{1}{2}\times10\times81 = 5\times81=405\space J\).

Answer:

405 joules