QUESTION IMAGE
Question
- $12m + 14n - 7m + 3n + 5$
- $10m + 12 + 5n + 3m - 3n$
- $13a + 4b + 3a - 2b$
- $n + 13 - 5$
- $19a + 2b + 11a - b$
- $18c + 4 + 2c$
- $4q + 18 + 11q$
- $13a + 9 + 9b + 12a - 7b$
- $13x + 4 + 2x$
- $3a + 15 + a$
- $18z + 10y + 3z - y$
- $10b + 98 + 16c + 30b - 6c$
- $p + 23 - 4$
- $2z + 5 + 3z$
- $12z + 12y + 13z - y$
- $4a + 13b - 2a + 2b + 25$
- $19a + 12b + a - 2b$
- $12z + 5 + 3z$
- $y + 56 - 13$
- $15m + 12n + 5m - 3n$
Let's solve each problem by combining like terms:
1) \( 12m + 14n - 7m + 3n + 5 \)
Step1: Combine like terms for \( m \)
\( 12m - 7m = 5m \)
Step2: Combine like terms for \( n \)
\( 14n + 3n = 17n \)
Step3: The constant term is \( 5 \)
So, \( 5m + 17n + 5 \)
2) \( 10m + 12 + 5n + 3m - 3n \)
Step1: Combine like terms for \( m \)
\( 10m + 3m = 13m \)
Step2: Combine like terms for \( n \)
\( 5n - 3n = 2n \)
Step3: The constant term is \( 12 \)
So, \( 13m + 2n + 12 \)
3) \( 13a + 4b + 3a - 2b \)
Step1: Combine like terms for \( a \)
\( 13a + 3a = 16a \)
Step2: Combine like terms for \( b \)
\( 4b - 2b = 2b \)
So, \( 16a + 2b \)
4) \( n + 13 - 5 \)
Step1: Combine constant terms
\( 13 - 5 = 8 \)
So, \( n + 8 \)
5) \( 19a + 2b + 11a - b \)
Step1: Combine like terms for \( a \)
\( 19a + 11a = 30a \)
Step2: Combine like terms for \( b \)
\( 2b - b = b \)
So, \( 30a + b \)
6) \( 18c + 4 + 2c \)
Step1: Combine like terms for \( c \)
\( 18c + 2c = 20c \)
Step2: The constant term is \( 4 \)
So, \( 20c + 4 \)
7) \( 4q + 18 + 11q \)
Step1: Combine like terms for \( q \)
\( 4q + 11q = 15q \)
Step2: The constant term is \( 18 \)
So, \( 15q + 18 \)
8) \( 13a + 9 + 9b + 12a - 7b \)
Step1: Combine like terms for \( a \)
\( 13a + 12a = 25a \)
Step2: Combine like terms for \( b \)
\( 9b - 7b = 2b \)
Step3: The constant term is \( 9 \)
So, \( 25a + 2b + 9 \)
9) \( 13x + 4 + 2x \)
Step1: Combine like terms for \( x \)
\( 13x + 2x = 15x \)
Step2: The constant term is \( 4 \)
So, \( 15x + 4 \)
10) \( 3a + 15 + a \)
Step1: Combine like terms for \( a \)
\( 3a + a = 4a \)
Step2: The constant term is \( 15 \)
So, \( 4a + 15 \)
11) \( 18z + 10y + 3z - y \)
Step1: Combine like terms for \( z \)
\( 18z + 3z = 21z \)
Step2: Combine like terms for \( y \)
\( 10y - y = 9y \)
So, \( 21z + 9y \)
12) \( 10b + 98 + 16c + 30b - 6c \)
Step1: Combine like terms for \( b \)
\( 10b + 30b = 40b \)
Step2: Combine like terms for \( c \)
\( 16c - 6c = 10c \)
Step3: The constant term is \( 98 \)
So, \( 40b + 10c + 98 \)
13) \( p + 23 - 4 \)
Step1: Combine constant terms
\( 23 - 4 = 19 \)
So, \( p + 19 \)
14) \( 2z + 5 + 3z \)
Step1: Combine like terms for \( z \)
\( 2z + 3z = 5z \)
Step2: The constant term is \( 5 \)
So, \( 5z + 5 \)
15) \( 12z + 12y + 13z - y \)
Step1: Combine like terms for \( z \)
\( 12z + 13z = 25z \)
Step2: Combine like terms for \( y \)
\( 12y - y = 11y \)
So, \( 25z + 11y \)
16) \( 4a + 13b - 2a + 2b + 25 \)
Step1: Combine like terms for \( a \)
\( 4a - 2a = 2a \)
Step2: Combine like terms for \( b \)
\( 13b + 2b = 15b \)
Step3: The constant term is \( 25 \)
So, \( 2a + 15b + 25 \)
17) \( 19a + 12b + a - 2b \)
Step1: Combine like terms for \( a \)
\( 19a + a = 20a \)
Step2: Combine like terms for \( b \)
\( 12b - 2b = 10b \)
So, \( 20a + 10b \)
18) \( 12z + 5 + 3z \)
Step1: Combine like terms for \( z \)
\( 12z + 3z = 15z \)
Step2: The constant term is \( 5 \)
So, \( 15z + 5 \)
19) \( y + 56 - 13 \)
Step1: Combine constant terms
\( 56 - 13 = 43 \)
So, \( y + 43 \)
20) \( 15m + 12n + 5m - 3n \)
Step1: Combine like terms for \( m \)
\( 15m + 5m = 20m \)
Step2: Combine like terms for \( n \)
\( 12n - 3n = 9n \)
So, \( 20m + 9n \)
Final Answers:
- \( \boldsymbol{5m + 17n + 5} \)
- \( \boldsymbol{13m + 2n + 12} \)
- \( \boldsymbol{16a + 2b} \)
- \( \boldsymbol{n + 8} \)
- \( \boldsymbol{30a + b} \)
- \( \boldsymbol{20c + 4} \)
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Let's solve each problem by combining like terms:
1) \( 12m + 14n - 7m + 3n + 5 \)
Step1: Combine like terms for \( m \)
\( 12m - 7m = 5m \)
Step2: Combine like terms for \( n \)
\( 14n + 3n = 17n \)
Step3: The constant term is \( 5 \)
So, \( 5m + 17n + 5 \)
2) \( 10m + 12 + 5n + 3m - 3n \)
Step1: Combine like terms for \( m \)
\( 10m + 3m = 13m \)
Step2: Combine like terms for \( n \)
\( 5n - 3n = 2n \)
Step3: The constant term is \( 12 \)
So, \( 13m + 2n + 12 \)
3) \( 13a + 4b + 3a - 2b \)
Step1: Combine like terms for \( a \)
\( 13a + 3a = 16a \)
Step2: Combine like terms for \( b \)
\( 4b - 2b = 2b \)
So, \( 16a + 2b \)
4) \( n + 13 - 5 \)
Step1: Combine constant terms
\( 13 - 5 = 8 \)
So, \( n + 8 \)
5) \( 19a + 2b + 11a - b \)
Step1: Combine like terms for \( a \)
\( 19a + 11a = 30a \)
Step2: Combine like terms for \( b \)
\( 2b - b = b \)
So, \( 30a + b \)
6) \( 18c + 4 + 2c \)
Step1: Combine like terms for \( c \)
\( 18c + 2c = 20c \)
Step2: The constant term is \( 4 \)
So, \( 20c + 4 \)
7) \( 4q + 18 + 11q \)
Step1: Combine like terms for \( q \)
\( 4q + 11q = 15q \)
Step2: The constant term is \( 18 \)
So, \( 15q + 18 \)
8) \( 13a + 9 + 9b + 12a - 7b \)
Step1: Combine like terms for \( a \)
\( 13a + 12a = 25a \)
Step2: Combine like terms for \( b \)
\( 9b - 7b = 2b \)
Step3: The constant term is \( 9 \)
So, \( 25a + 2b + 9 \)
9) \( 13x + 4 + 2x \)
Step1: Combine like terms for \( x \)
\( 13x + 2x = 15x \)
Step2: The constant term is \( 4 \)
So, \( 15x + 4 \)
10) \( 3a + 15 + a \)
Step1: Combine like terms for \( a \)
\( 3a + a = 4a \)
Step2: The constant term is \( 15 \)
So, \( 4a + 15 \)
11) \( 18z + 10y + 3z - y \)
Step1: Combine like terms for \( z \)
\( 18z + 3z = 21z \)
Step2: Combine like terms for \( y \)
\( 10y - y = 9y \)
So, \( 21z + 9y \)
12) \( 10b + 98 + 16c + 30b - 6c \)
Step1: Combine like terms for \( b \)
\( 10b + 30b = 40b \)
Step2: Combine like terms for \( c \)
\( 16c - 6c = 10c \)
Step3: The constant term is \( 98 \)
So, \( 40b + 10c + 98 \)
13) \( p + 23 - 4 \)
Step1: Combine constant terms
\( 23 - 4 = 19 \)
So, \( p + 19 \)
14) \( 2z + 5 + 3z \)
Step1: Combine like terms for \( z \)
\( 2z + 3z = 5z \)
Step2: The constant term is \( 5 \)
So, \( 5z + 5 \)
15) \( 12z + 12y + 13z - y \)
Step1: Combine like terms for \( z \)
\( 12z + 13z = 25z \)
Step2: Combine like terms for \( y \)
\( 12y - y = 11y \)
So, \( 25z + 11y \)
16) \( 4a + 13b - 2a + 2b + 25 \)
Step1: Combine like terms for \( a \)
\( 4a - 2a = 2a \)
Step2: Combine like terms for \( b \)
\( 13b + 2b = 15b \)
Step3: The constant term is \( 25 \)
So, \( 2a + 15b + 25 \)
17) \( 19a + 12b + a - 2b \)
Step1: Combine like terms for \( a \)
\( 19a + a = 20a \)
Step2: Combine like terms for \( b \)
\( 12b - 2b = 10b \)
So, \( 20a + 10b \)
18) \( 12z + 5 + 3z \)
Step1: Combine like terms for \( z \)
\( 12z + 3z = 15z \)
Step2: The constant term is \( 5 \)
So, \( 15z + 5 \)
19) \( y + 56 - 13 \)
Step1: Combine constant terms
\( 56 - 13 = 43 \)
So, \( y + 43 \)
20) \( 15m + 12n + 5m - 3n \)
Step1: Combine like terms for \( m \)
\( 15m + 5m = 20m \)
Step2: Combine like terms for \( n \)
\( 12n - 3n = 9n \)
So, \( 20m + 9n \)
Final Answers:
- \( \boldsymbol{5m + 17n + 5} \)
- \( \boldsymbol{13m + 2n + 12} \)
- \( \boldsymbol{16a + 2b} \)
- \( \boldsymbol{n + 8} \)
- \( \boldsymbol{30a + b} \)
- \( \boldsymbol{20c + 4} \)
- \( \boldsymbol{15q + 18} \)
- \( \boldsymbol{25a + 2b + 9} \)
- \( \boldsymbol{15x + 4} \)
- \( \boldsymbol{4a + 15} \)
- \( \boldsymbol{21z + 9y} \)
- \( \boldsymbol{40b + 10c + 98} \)
- \( \boldsymbol{p + 19} \)
- \( \boldsymbol{5z + 5} \)
- \( \boldsymbol{25z + 11y} \)
- \( \boldsymbol{2a + 15b + 25} \)
- \( \boldsymbol{20a + 10b} \)
- \( \boldsymbol{15z + 5} \)
- \( \boldsymbol{y + 43} \)
- \( \boldsymbol{20m + 9n} \)