Question

2.08 - solve linear equations with fractions
due sunday by 11:59pm points 100 submitting an external tool available se
question
solve: $\frac{1}{2}a+\frac{2}{3}=\frac{3}{4}a - \frac{1}{3}$.
provide your answer below:
a = □

Explanation:

Step1: Move terms with a to one - side

Subtract $\frac{1}{2}a$ from both sides and add $\frac{1}{3}$ to both sides:
$\frac{2}{3}+\frac{1}{3}=\frac{3}{4}a-\frac{1}{2}a$

Step2: Simplify both sides

On the left - hand side, $\frac{2 + 1}{3}=1$. On the right - hand side, find a common denominator for the a terms. The common denominator of 4 and 2 is 4, so $\frac{3}{4}a-\frac{1}{2}a=\frac{3}{4}a-\frac{2}{4}a=\frac{3 - 2}{4}a=\frac{1}{4}a$. So we have $1=\frac{1}{4}a$.

Step3: Solve for a

Multiply both sides by 4 to isolate a. $4\times1 = 4\times\frac{1}{4}a$, which gives $a = 4$.

Answer:

$a = 4$