Question

a 5.00 l gas sample at 85 kpa is compressed to 3.50 l. find the new pressure.

Explanation:

Step1: Recall Boyle's Law

Boyle's Law states that \(P_1V_1 = P_2V_2\) (for a gas at constant temperature), where \(P_1\) and \(V_1\) are the initial pressure and volume, and \(P_2\) and \(V_2\) are the final pressure and volume.
Given \(P_1=85\ \text{kPa}\), \(V_1 = 5.00\ \text{L}\), and \(V_2=3.50\ \text{L}\).

Step2: Solve for \(P_2\)

Rearrange the formula \(P_2=\frac{P_1V_1}{V_2}\).
Substitute the values: \(P_2=\frac{85\ \text{kPa}\times5.00\ \text{L}}{3.50\ \text{L}}\).
First, calculate \(85\times5.00 = 425\).
Then, \(\frac{425}{3.50}\approx121.43\ \text{kPa}\).

Answer:

The new pressure is approximately \(121\ \text{kPa}\).