Question

you’re trying to figure out how many solutions the equation has. let’s solve this equation step by step. you’re trying to get rid of the parentheses on the left by distributing the \\(\frac{1}{2}\\) to the 6x and to the 2. you can think of this as \\((\frac{1}{2} \cdot 6x) + (\frac{1}{2} \cdot 2)\\). \\(\frac{1}{2}(6x + 2) = 3x\\) \\(\square + \square = 3x\\)

Explanation:

Step1: Distribute $\frac{1}{2}$ to $6x$

Calculate $\frac{1}{2} \cdot 6x$.
$\frac{1}{2} \cdot 6x = \frac{6x}{2} = 3x$.

Step2: Distribute $\frac{1}{2}$ to $2$

Calculate $\frac{1}{2} \cdot 2$.
$\frac{1}{2} \cdot 2 = \frac{2}{2} = 1$.

Answer:

The first box is $3x$ and the second box is $1$, so the filled equation is $3x + 1 = 3x$.