Question

in δwxy, w = 69 inches, x = 96 inches and y = 57 inches. find the area of δwxy to the nearest 10th of an square inch.

Explanation:

Step1: Calculate the semi - perimeter

The semi - perimeter $s$ of a triangle with side lengths $a$, $b$, and $c$ is given by $s=\frac{a + b + c}{2}$. Here, $a = 69$, $b = 96$, $c = 57$, so $s=\frac{69+96 + 57}{2}=\frac{222}{2}=111$ inches.

Step2: Use Heron's formula

Heron's formula for the area $A$ of a triangle is $A=\sqrt{s(s - a)(s - b)(s - c)}$. Substitute $s = 111$, $a = 69$, $b = 96$, $c = 57$ into the formula:

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Answer:

$1943.2$ square inches