Question

write the vector $\langle - 4,11\
angle$ in the form $a \mathbf{i}+b \mathbf{j}$.
$\langle - 4,11\
angle=\square \mathbf{i}+\square \mathbf{j}$

Explanation:

Step1: Recall vector component form

A vector $\langle x, y
angle$ in the form $a\mathbf{i} + b\mathbf{j}$ has $a$ as the $x$-component and $b$ as the $y$-component.
For the vector $\langle -4, 11
angle$, the $x$-component is $-4$ and the $y$-component is $11$.

Step2: Write in $a\mathbf{i} + b\mathbf{j}$ form

Substitute $a = -4$ and $b = 11$ into $a\mathbf{i} + b\mathbf{j}$.
So, $\langle -4, 11
angle = -4\mathbf{i} + 11\mathbf{j}$.

Answer:

$-4\mathbf{i} + 11\mathbf{j}$ (where the first box is $-4$ and the second box is $11$)