Question

write two monomials with a product of -84a^6b^10.

Explanation:

Step1: Factor -84

We can write -84 as - 12×7.

Step2: Split the powers of variables

For the variable part \(a^{6}b^{10}\), we can split it as \(a^{3}b^{5}\times a^{3}b^{5}\).
So two monomials can be \(-12a^{3}b^{5}\) and \(7a^{3}b^{5}\) (answers may vary).

Answer:

\(-12a^{3}b^{5}\), \(7a^{3}b^{5}\)