Question

write the following sum as a single logarithm. assume all variables are positive.

\\(\log_{4}(6) + \log_{4}(b) =\\)

the answer format in lowercase characters is: log_base (number)
spaces in the answer are optional.

Explanation:

Step1: Identify the logarithmic property

Apply the product rule of logarithms.

$$\log_a(x) + \log_a(y) = \log_a(xy)$$

Step2: Simplify the expression

Multiply the arguments within the same base.

$$\log_4(6) + \log_4(b) = \log_4(6 \cdot b) = \log_4(6b)$$

Answer:

\(\log_4(6b)\)