Question

write the following equation in standard form. then solve.
4q² - 2q = 3q² - 5q + 40

the equation in standard form is

Explanation:

Step1: Move all terms to left side

$4q^2 - 2q - 3q^2 + 5q - 40 = 0$

Step2: Combine like terms

$q^2 + 3q - 40 = 0$

Step3: Factor the quadratic

$(q + 8)(q - 5) = 0$

Step4: Solve for q

Set each factor equal to 0:
$q + 8 = 0 \implies q = -8$
$q - 5 = 0 \implies q = 5$

Answer:

The equation in standard form is $q^2 + 3q - 40 = 0$.
The solutions are $q = -8$ and $q = 5$.