Question

write the equation of a line in slope-intercept form with a slope of \\(\frac{2}{3}\\) and a y-intercept of -18.\\(\bigcirc\\ y = -\frac{2}{3}x - 18\\)\\(\bigcirc\\ y = -18x + \frac{2}{3}\\)\\(\bigcirc\\ y = \frac{2}{3}x - 18\\)\\(\bigcirc\\ y = \frac{2}{3}x + 18\\)

Explanation:

Step1: Recall slope-intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept.

Step2: Substitute the given values

We are given that the slope $m=\frac{2}{3}$ and the y - intercept $b = - 18$. Substituting these values into the slope - intercept form $y=mx + b$, we get $y=\frac{2}{3}x+(-18)$, which simplifies to $y=\frac{2}{3}x - 18$.

Answer:

$y=\frac{2}{3}x - 18$ (corresponding to the option $y=\frac{2}{3}x - 18$)