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Question
write the equation of the line that passes through the points \\((7, -4)\\) and \\((-1, 3)\\), first in point-slope form, and then in slope-intercept form.
the slope of the line is dropdown
when the point \\((7, -4)\\) is used, the point-slope form of the line is dropdown
the slope-intercept form of the line is dropdown
Calculate the slope of the line
We find the slope \(m\) using the coordinates \((x_1, y_1) = (7, -4)\) and \((x_2, y_2) = (-1, 3)\).
Using the slope formula:
We apply Variable Substitution to evaluate:
Write the point-slope form
The point-slope equation is \(y - y_1 = m(x - x_1)\).
Using the point \((7, -4)\) and \(m = -\frac{7}{8}\), we substitute:
Simplifying the left side gives:
Convert to slope-intercept form
We isolate \(y\) to find the slope-intercept form \(y = mx + b\).
Distribute the slope:
Subtract 4 from both sides:
Combine the constants:
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Write the equation of the line that passes through the points \((7, -4)\) and \((-1, 3)\), first in point-slope form, and then in slope-intercept form.
The slope of the line is <blank>\(-\frac{7}{8}\)</blank>
When the point \((7, -4)\) is used, the point-slope form of the line is <blank>\(y + 4 = -\frac{7}{8}(x - 7)\)</blank>
The slope-intercept form of the line is <blank>\(y = -\frac{7}{8}x + \frac{17}{8}\)</blank>