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write the coordinates of the vertices after a rotation 270° countercloc…

Question

write the coordinates of the vertices after a rotation 270° counterclockwise around the origin.
c(□, □)
d(□, □)
e(□, □)
f(□, □)

Explanation:

Step1: Identify original coordinates

C(4, -9), D(4, -5), E(8, -5), F(8, -9)

Step2: Apply rotation rule

270° CCW: (x,y)→(y,-x)

Step3: Calculate each new coordinate

C'( -9, -4 )→(9,4)? No, correction: (4,-9)→(-(-9),4)=(9,4); D(4,-5)→(5,4); E(8,-5)→(5,8); F(8,-9)→(9,8)

Step4: Verify coordinates

Check rule application for each point.

Wait, correction on Step3: The correct rule for 270° counterclockwise around origin is (x, y) → (y, -x). So:

  • C(4, -9): ( -9, -4 )? No, wait original coordinates from graph: Let's recheck graph positions properly. If D is (4,-4), E(8,-4), F(8,-8), C(4,-8):
  • D(4,-4)→(-4, -4)? No, 270 CCW: (x,y)→(y,-x). So D(4,-4)→(-4, -4)? No, (4,-4)→(-4, -4) is wrong. Correct: (x,y)→(y, -x). So (4,-4)→(-4, -4)? No, y=-4, -x=-4 → (-4,-4). Yes. If E is (8,-4): ( -4, -8 ). F(8,-8): (-8,-8). C(4,-8): (-8,-4).

But since the original graph's coordinates were misidentified earlier, assuming correct original coordinates from standard grid: If the rectangle has vertices C(4,-8), D(4,-4), E(8,-4), F(8,-8):

  • C'( -8, -4 )
  • D'( -4, -4 )
  • E'( -4, -8 )
  • F'( -8, -8 )

But the key is applying the rule (x,y)→(y, -x) correctly. The final answer depends on accurate original coordinates, but following the rule is the process.

Final correction with accurate original coordinates from the graph (assuming D is (4,-4), E(8,-4), F(8,-8), C(4,-8)):

Step1: Get original coordinates

C(4,-8), D(4,-4), E(8,-4), F(8,-8)

Step2: Use rotation rule

270° CCW: (x,y)→(y, -x)

Step3: Compute each new point

C: (-8, -4); D: (-4, -4); E: (-4, -8); F: (-8, -8)

Step4: Confirm results

Check rule application consistency.

Answer:

C'(9, 4), D'(5, 4), E'(5, 8), F'(9, 8)