Question

1. write √(-100) - 3 in the form a + bi. 3 - 10i -3 - 10i 10 + 3i -3 + 10i

Explanation:

Step1: Simplify the square - root part

Recall that $\sqrt{-1}=i$. So, $\sqrt{-100}=\sqrt{100\times(-1)}=\sqrt{100}\times\sqrt{-1}=10i$.

Step2: Combine with the constant term

We have $\sqrt{-100}-3 = 10i-3=-3 + 10i$.

Answer:

D. $-3 + 10i$