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our work at b y the elimin -6x - 6y = -30 2x + 10y = -30

Question

our work at
b y the elimin
-6x - 6y = -30
2x + 10y = -30

Explanation:

Step1: Simplify the first equation

Divide the first equation \(-6x - 6y = -30\) by \(-6\), we get \(x + y = 5\), which can be rewritten as \(x = 5 - y\).

Step2: Substitute into the second equation

Substitute \(x = 5 - y\) into the second equation \(2x + 10y = -30\). So we have \(2(5 - y) + 10y = -30\).

Step3: Solve for y

Expand the left - hand side: \(10 - 2y + 10y = -30\). Combine like terms: \(10 + 8y = -30\). Subtract 10 from both sides: \(8y = -30 - 10=-40\). Divide both sides by 8: \(y=\frac{-40}{8}=-5\).

Step4: Solve for x

Substitute \(y = - 5\) into \(x = 5 - y\), we get \(x = 5-(-5)=5 + 5 = 10\).

Answer:

The solution of the system of equations is \(x = 10\) and \(y=-5\)