Question

which shows the equation below written in the form $ax^{2}+bx + c = 0$? $2x^{2}-2=-5x - 1$ a $2x^{2}+5x - 3 = 0$ b. $2x^{2}-5x - 1 = 0$ c. $2x^{2}-5x - 3 = 0$ d. $2x^{2}+5x - 1 = 0$

Explanation:

Step1: Move all terms to one side

Add \(5x\) and \(1\) to both sides of the equation \(2x^{2}-2=-5x - 1\).
\(2x^{2}-2 + 5x+1=-5x - 1+5x + 1\)

Step2: Simplify the equation

Combine like - terms: \(2x^{2}+5x+( - 2 + 1)=0\), which simplifies to \(2x^{2}+5x - 1=0\).

Answer:

D. \(2x^{2}+5x - 1=0\)