Question

1. which has a quotient of 0.6?

a 0.204 ÷ 0.034 b 0.204 ÷ 0.34 c 2.04 ÷ 0.034 d 2.04 ÷ 0.34

1. the ocean rises and falls each day due to tides. the bay of fundy in

canada has some of the highest tides in the world. its tidewater rises
about 53.478 feet and falls the same amount afterwards, twice a day.
a. write an expression that can be used to find the total feet the tide
rises and falls each day.

b. write an expression that can be used to find the total feet the tide
rises and falls over a one - week period.

c. how many total feet does the tide rise and fall over a one - week period?

1. a 0.5 - pound bunch of bananas costs $0.22 and 1 pound of oranges cost

$2.39. if a person has $20, which expression could be used to determine
how much change the person would get after purchasing the 0.5 - pound
bunch of bananas and 3.25 pounds of oranges?
a 20 − 0.22 + (2.39 × 3.25) c 20 − 0.22 + (3.25 × 2.39)
b 0.22 + (2.39 × 3.25) − 20 d 0.22 + (0.5 × 3.25) − 20

1. a bag of equally - sized rhinestones weighs 16 ounces. each rhinestone

weighs 0.016 ounce. if you have 2 bags of rhinestones, how many
rhinestones do you have?

1. what is the value of the expression?

7.09 − (1.36 × 4.125) + (3.28 ÷ 0.04)
a 8.85 b 9.68 c 83.39 d 83.48

1. remy is saving money to buy a new video game console. the console

costs $199.95. remy makes $40.50 each week babysitting. how many total
weeks will he need to babysit to save up enough money for the video
game console? explain your reasoning.

Explanation:

Question 8

Step1: Calculate each option's quotient

• Option A: $0.204\div0.034 = \frac{0.204}{0.034}=6$
• Option B: $0.204\div0.34=\frac{0.204}{0.34} = 0.6$
• Option C: $2.04\div0.034=\frac{2.04}{0.034}=60$
• Option D: $2.04\div0.34=\frac{2.04}{0.34} = 6$

Step1: Analyze the tide movement

The tide rises 53.478 feet and falls 53.478 feet, twice a day. So for one cycle (rise and fall), it's \(53.478\times2\) feet, and since it happens twice a day, the total per day is \(2\times(53.478 + 53.478)=4\times53.478\) or simpler, each time it rises and falls, the total for one rise - fall is \(53.478\times2\), and twice a day, so \(2\times(53.478\times2)=4\times53.478\) or \(53.478\times4\). But more accurately, each day, it rises twice and falls twice? Wait, no, "rises about 53.478 feet and falls the same amount afterwards, twice a day". So each "rise - fall" is one event, twice a day. So per event: rise 53.478, fall 53.478, so per event total is \(53.478+53.478 = 53.478\times2\). And twice a day, so total per day: \(2\times(53.478\times2)=53.478\times4\) or \(2\times2\times53.478\). But the simplest expression: since each time it rises and falls, that's \(53.478\times2\) feet per cycle, and 2 cycles per day, so \(2\times(53.478\times2)=4\times53.478\) or \(53.478\times4\). But maybe the intended is: each day, it rises twice (53.478 each) and falls twice (53.478 each), so total rise - fall per day is \(2\times53.478+2\times53.478 = 4\times53.478\), or \(2\times(53.478 + 53.478)=2\times2\times53.478\). But the most straightforward: for each "rise and fall" (once rise, once fall), it's \(53.478\times2\) feet, and twice a day, so the expression is \(2\times(53.478\times2)=4\times53.478\) or \(53.478\times4\). Alternatively, if "twice a day" means two rises and two falls, then total rise: \(2\times53.478\), total fall: \(2\times53.478\), so total per day: \(2\times53.478+2\times53.478 = 4\times53.478\).

Step1 (corrected):

The tide rises 53.478 feet and then falls 53.478 feet, and this happens twice a day. So for each occurrence of rising and falling, the total distance is \(53.478 + 53.478=53.478\times2\) feet. Since this happens twice a day, the total feet per day is \(2\times(53.478\times2)=4\times53.478\) or \(53.478\times4\). But a simpler way: each day, there are 2 cycles of rise and fall. Each cycle (rise + fall) is \(53.478\times2\) feet. So the expression is \(2\times(53.478\times2)\) or \(53.478\times4\). But the most direct expression based on the problem statement: "rises about 53.478 feet and falls the same amount afterwards, twice a day". So per day, number of rises: 2, number of falls: 2. So total rise: \(2\times53.478\), total fall: \(2\times53.478\), so total per day: \(2\times53.478+2\times53.478 = 4\times53.478\). So the expression is \(4\times53.478\) or \(53.478\times4\).

Step1: Use the daily expression

From part A, the daily total is \(4\times53.478\). For a week (7 days), we multiply by 7. So the expression is \(7\times(4\times53.478)\) or \(4\times53.478\times7\).

Answer:

B. \(0.204 \div 0.34\)

Question 9

Part A