Question

which integer is closest to \\(\sqrt3{69}\\)?

Explanation:

Step1: Find nearby perfect cubes

$4^3 = 64$, $5^3 = 125$

Step2: Calculate differences to 69

$|69 - 64| = 5$, $|69 - 125| = 56$

Step3: Compare differences

5 < 56, so 69 is closer to 64.

Answer:

4