Question

6 which equation has a solution for $n = \frac{4}{5}$? a $n - 1 = \frac{3}{5}$ b $10n = 8$ c $8n = 10$ d $1\frac{1}{4} + n = 3$

Explanation:

Step1: Check Option A

Substitute \( n = \frac{4}{5} \) into \( n - 1 \). We get \( \frac{4}{5}-1=\frac{4}{5}-\frac{5}{5}=-\frac{1}{5}
eq\frac{3}{5} \). So A is wrong.

Step2: Check Option B

Substitute \( n = \frac{4}{5} \) into \( 10n \). We calculate \( 10\times\frac{4}{5}=\frac{40}{5} = 8 \), which equals the right - hand side of the equation \( 10n = 8 \).

Step3: Check Option C (Optional, since we found the correct one, but for completeness)

Substitute \( n=\frac{4}{5} \) into \( 8n \). We get \( 8\times\frac{4}{5}=\frac{32}{5}=6.4
eq10 \). So C is wrong.

Step4: Check Option D (Optional)

First, convert \( 1\frac{1}{4} \) to an improper fraction, \( 1\frac{1}{4}=\frac{5}{4} \). Substitute \( n = \frac{4}{5} \) into \( 1\frac{1}{4}+n \), we have \( \frac{5}{4}+\frac{4}{5}=\frac{25 + 16}{20}=\frac{41}{20}=2.05
eq3 \). So D is wrong.

Answer:

B. \( 10n = 8 \)