Question

which is the equation of $2^{x - 1}-7 = 9$ after it is reduced so that both sides of the equation are exponential functions with the same base?\
$2^{x - 1}=2^{4}$\
$2^{x - 1}-7^{0}=3^{2}$\
$2^{x - 1}-7^{0}=3^{2}$\
$2^{x - 1}=4^{2}$

Explanation:

Step1: Isolate the exponential term

$2^{x-1} - 7 + 7 = 9 + 7$
$2^{x-1} = 16$

Step2: Rewrite constant as base-2 exponent

Since $16 = 2^4$, substitute:
$2^{x-1} = 2^4$

Answer:

$2^{x-1} = 2^4$