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which are characteristics of the graph of the parent absolute value fun…

Question

which are characteristics of the graph of the parent absolute value function?
the graph is symmetric with respect to the y - axis. the graph is a \v\ with vertex at the point (0,0).
the two halves of the graph make 45° angles with the the two halves of the graph make 30° angles with the
x - axis. x - axis.
the graph is symmetric with respect to the x - axis.

Explanation:

Step1: Analyze symmetry about y - axis

For the parent absolute - value function \(y = |x|\), if we replace \(x\) with \(-x\), we get \(y=|-x|=|x|\). So, \(y = |x|\) is symmetric about the \(y\) - axis.

Step2: Analyze the shape and vertex

The parent absolute - value function \(y = |x|\) has the form \(y=

$$\begin{cases}x, & x\geq0\\-x, & x < 0\end{cases}$$

\). Its graph is a "V" - shape. When \(x = 0\), \(y=0\), so the vertex is at \((0,0)\).

Step3: Analyze the angle with the x - axis

For \(y = x\) (when \(x\geq0\)), the slope \(m = 1\). The angle \(\theta\) that the line \(y = x\) makes with the \(x\) - axis is given by \(\tan\theta=1\), so \(\theta = 45^{\circ}\). For \(y=-x\) (when \(x < 0\)), the slope \(m=- 1\), and the angle that the line makes with the positive \(x\) - axis (in the second quadrant) is also \(45^{\circ}\) (since the magnitude of the slope is \(1\)).

Step4: Analyze symmetry about x - axis

If a graph is symmetric about the \(x\) - axis, for every point \((x,y)\) on the graph, the point \((x, - y)\) is also on the graph. For \(y = |x|\), if we take a point \((1,1)\) (since \(y=|1| = 1\)), the point \((1,-1)\) is not on the graph \(y = |x|\) (because \(|-1|
eq - 1\)). So, the graph is not symmetric about the \(x\) - axis.

Answer:

The graph is symmetric with respect to the \(y\) - axis. The graph is a "V" with vertex at the point \((0,0)\). The two halves of the graph make \(45^{\circ}\) angles with the \(x\) - axis.