Question

1 when three squares are joined at their vertices to form a right triangle, the combined area of the two smaller squares is the same as the area of the largest square.
which three squares do not support this statement?
a 5 in, 12 in, 169 in²
b 64 in², 121 in², 20 in
c 6 in, 8 in, 100 in²
d 3 in, 4 in, 5 in

Explanation:

Step1: Calculate areas for Option A

Small squares: $5^2=25$, $12^2=144$. Sum: $25+144=169$. Large square area: 169. Supports the statement.

Step2: Calculate areas for Option B

Small squares: 64, 121. Sum: $64+121=185$. Large square area: $20^2=400$. $185≠400$. Does not support.

Step3: Calculate areas for Option C

Small squares: $6^2=36$, $8^2=64$. Sum: $36+64=100$. Large square area:100. Supports the statement.

Step4: Calculate areas for Option D

Small squares: $4^2=16$, $9^2=81$. Sum: $16+81=97$. Large square side:5, area:25. $97≠25$. Does not support.

Answer:

B, D