Question

what is the volume, in cubic inches, of a cylinder with a height of 4 inches and a base radius of 8 inches, to the nearest tenths place?
answer attempt 1 out of 3
v =

Explanation:

Step1: Recall the formula for the volume of a cylinder

The formula for the volume \( V \) of a cylinder is \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.

Step2: Identify the given values

We are given that the radius \( r = 8 \) inches and the height \( h=4 \) inches.

Step3: Substitute the values into the formula

Substitute \( r = 8 \) and \( h = 4 \) into the formula \( V=\pi r^{2}h \). So we have \( V=\pi\times(8)^{2}\times4 \).
First, calculate \( 8^{2}=64 \). Then, multiply \( 64\times4 = 256 \). So now the formula becomes \( V=\pi\times256 \).

Step4: Calculate the numerical value

Using the approximation \( \pi\approx3.14159 \), we get \( V\approx3.14159\times256 \).
Calculate \( 3.14159\times256 = 804.24704 \).

Step5: Round to the nearest tenths place

To round \( 804.24704 \) to the nearest tenths place, we look at the hundredths digit, which is 4. Since \( 4<5 \), we round down. So \( 804.24704\approx804.2 \).

Answer:

\( 804.2 \)