Question

what is the vertex of the quadratic function ( f(x) = (x - 6)(x + 2) )?

Explanation:

Step1: Find x-intercepts

Roots are $x=6$ and $x=-2$

Step2: Calculate vertex x-coordinate

$x = \frac{6 + (-2)}{2} = 2$

Step3: Find vertex y-coordinate

Substitute $x=2$ into $f(x)$:
$f(2) = (2-6)(2+2) = (-4)(4) = -16$

Answer:

$(2, -16)$